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Show that for odd positive integer to be a perfect square, it should be of the form
8k +1. Let a=2m+1
Ans: Squaring both sides we get a2 = 4m (m +1) + 1
∴ product of two consecutive numbers is always even
m(m+1)=2k
a2=4(2k)+1 a2 = 8 k + 1
Hence proved
howto know whether a region is bounded or not
1/cos(x-a)cos(x-b)
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G raph y = sec ( x ) Solution: As with tangent we will have to avoid x's for which cosine is zero (recall that sec x =1/ cos x) Secant will not present at
im having trouble with this problem: 6tons 1500lb/5
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