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Graph y = sec ( x )
Solution: As with tangent we will have to avoid x's for which cosine is zero (recall that sec x =1/ cos x)
Secant will not present at
x = ........, - 5 ∏/2 , - 3 ∏/2 , - ∏/2 , ∏/2, 3 ∏/2 , 5 ∏/2 ,........
and the graph will have asymptotes at these points. Following is the graph of secant on the range - 5 ∏/2 Notice as well that the graph is always greater than 1 & less than -1. It should not be terribly surprising. Remember that -1 ≤ cos ( x ) ≤ 1 . Hence, one divided by something less than one will be greater than 1. Also, 1 / ±1 = ±1 and hence we get the following ranges for secant. sec (? x) ≥ 1 and sec (? x) ≤ -1
Notice as well that the graph is always greater than 1 & less than -1. It should not be terribly surprising. Remember that -1 ≤ cos ( x ) ≤ 1 . Hence, one divided by something less than one will be greater than 1. Also, 1 / ±1 = ±1 and hence we get the following ranges for secant.
sec (? x) ≥ 1 and sec (? x) ≤ -1
Find out the determinant: Find out the determinant of the following 3 x 3 matrix, expanding about row 1. Solution:
The value of y that minimizes the sum of the two distances from (3,5) to (1,y) and from (1,y) to (4,9) can be written as a/b where a and b are coprime positive integers. Find a+b.
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uses of maths concept
joey asked 30 randomly selected students if they drank milk, juice, or bottled water with their lunch. He found that 9 drank milk, 16 drank juice, and 5 drank bottled water. If the
-15divided by(-1_-4
25 cl=____________L
Prove that the Digraph of a partial order has no cycle of length greater than 1. Assume that there exists a cycle of length n ≥ 2 in the digraph of a partial order ≤ on a set A
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