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Graph y = sec ( x )
Solution: As with tangent we will have to avoid x's for which cosine is zero (recall that sec x =1/ cos x)
Secant will not present at
x = ........, - 5 ∏/2 , - 3 ∏/2 , - ∏/2 , ∏/2, 3 ∏/2 , 5 ∏/2 ,........
and the graph will have asymptotes at these points. Following is the graph of secant on the range - 5 ∏/2 Notice as well that the graph is always greater than 1 & less than -1. It should not be terribly surprising. Remember that -1 ≤ cos ( x ) ≤ 1 . Hence, one divided by something less than one will be greater than 1. Also, 1 / ±1 = ±1 and hence we get the following ranges for secant. sec (? x) ≥ 1 and sec (? x) ≤ -1
Notice as well that the graph is always greater than 1 & less than -1. It should not be terribly surprising. Remember that -1 ≤ cos ( x ) ≤ 1 . Hence, one divided by something less than one will be greater than 1. Also, 1 / ±1 = ±1 and hence we get the following ranges for secant.
sec (? x) ≥ 1 and sec (? x) ≤ -1
(1 0 3 21 -1 1 -1 1) find A-1
give me some examples on continuity
Heaviside or step function limit : Calculates the value of the following limit. Solution This function is frequently called either the Heaviside or step function. We
fixed cost of $1400 ,printing cost of .40 cents -each item to sell for $1.05. what is linear cost function, linear revenue function and number of items to be sold to make a profit
-1+5-100=?
The locus of the midpoint of the chords of an ellipse which are drawn through an end of minor axis is called
What are some of the interestingmodern developments in cruise control systems that contrast with comparatively basic old systems
finite or infinite 1]A={4,5,6,....}
the graph of relation y=f(x) respect to x=2 straight line is symmetrical then which is correct; (option) a) f(x+2)=f(x_2),b)f(2+x)=f(2_x),c)f(x)=f(_x),d)f(x)=_f(_x)
1-tan^2 A/1+tan^2 = cos A - sinA/cos A
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