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Graph y = sec ( x )
Solution: As with tangent we will have to avoid x's for which cosine is zero (recall that sec x =1/ cos x)
Secant will not present at
x = ........, - 5 ∏/2 , - 3 ∏/2 , - ∏/2 , ∏/2, 3 ∏/2 , 5 ∏/2 ,........
and the graph will have asymptotes at these points. Following is the graph of secant on the range - 5 ∏/2 Notice as well that the graph is always greater than 1 & less than -1. It should not be terribly surprising. Remember that -1 ≤ cos ( x ) ≤ 1 . Hence, one divided by something less than one will be greater than 1. Also, 1 / ±1 = ±1 and hence we get the following ranges for secant. sec (? x) ≥ 1 and sec (? x) ≤ -1
Notice as well that the graph is always greater than 1 & less than -1. It should not be terribly surprising. Remember that -1 ≤ cos ( x ) ≤ 1 . Hence, one divided by something less than one will be greater than 1. Also, 1 / ±1 = ±1 and hence we get the following ranges for secant.
sec (? x) ≥ 1 and sec (? x) ≤ -1
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If sin? = 1/2 , show that 3cos?-4cos 3 ? = 0. Ans: Sin ? = ½ ⇒ ? = 30 o Substituting in place of ? =30 o . We get 0.
E1) Why don't you think of some activities for the same purpose now? E2) Suggest, in detail, another activity for helping a child grasp the algorithm for division. We come to
sin 51+cos 81
The light on a lighthouse blinks 45 times a minute. How long will it take the light to blink 405 times? Divide 405 by 45 to get 9 minutes.
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Circle Well, let's recall just what a circle is. A circle is all the points which are the similar distance, r - called the radius, from a point, ( h, k ) - called the center. I
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