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Speedup
First, we take the speedup factor which is we see how much speed up performance we achieve by pipelining. First we take ideal case for measuring the speedup.
Let n be total number of tasks executed during m phases of pipelines.
Then m phases can process n tasks in clock cycles = m + (n-1)
Time taken to execute with no pipelining = m.n
Speedup because of pipelining = m.n/ [m + (n-1)].
As n>= ∞ There is speedup of n times over non-pipelined execution.
find cos(x) and sin(x) an pseudocode (while loop
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