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Explain propene
In propene, the H3C-C bond dipole adds vectorially to the smaller H-C bond dipole; the resultant is smaller than the H3C-C bond dipole itself, as the following diagram shows. In 2-methylpropene, the resultant of the two H3C-C bond dipoles is about equal in magnitude to one H3C-C bond dipole. (This can be shown analytically if we suppose 120° bond angles.) 2-Methylpropene has a somewhat greater dipole moment. (In the following vector analysis, the H-C bond dipoles of the CH2 groups are ignored due to they cancel in the comparison of the two molecules.)
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Show by means of equations and reagents, how the following conversion would be achieved? Propyne to butanoic acid
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