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Explain Memory Mapped I/O Scheme.
Memory Mapped I/O Scheme: In this scheme there is only one address space. Address space is explained as all possible addresses which microprocessor can generate. Several addresses are assigned to memories and several addresses to I/O devices. This I/O device is also function as a memory location and one address is assigned to this. In this scheme all the data transfer instructions of the microprocessor can be utilized for both memories with I/O device. This scheme is appropriate for a small system.
Explain protected mode interrupt. In this mode, interrupts have exactly similar assignments as in real mode, but the interrupt vector table is not same. In place of interrupt
Q. The block diagram of Figure represents a multi loop control system. (a) Determine the transfer function C(s)/R(s). (b) For G 2 G 3 H 2 = 1, evaluate C(s)/R(s).
Q. Define amplification factor? Amplification factor μ It is the ratio of the drain -source voltage (ΔVDS) to the change in the gate to source voltage (ΔV GS ) at constan
High Level Language ( third Generation Language ) The difficulties of low level languages are overcome by high level languages. In assembly language mnemonics were used
Explain the Bidirectional Shift Registers? A Reversible or A Bidirectional shift register is one in which the data can be shift either left or right. D flip-flops are used by
different types of probes used in multimeter
Explain Resistivity. Resistivity : Resistance R of a wire containing cross-sectional area A and length L maintain the relationship, - R α L and R α 1/A; that is resulting R α
Explain the operation of IRET instruction. What memory locations contain the vector for an INT 34 instruction? The Interrupt return (IRET) instruction is utilized only along w
Q. Illustrate working of Differential Amplifier? Figure shows a weighted differencing amplifier, where "weighted" refers to the fact that the output voltage has the form v o =
An audiomessage is band-limited to 15 kHz, sampled at twice the Nyquist rate, and encoded by a 12-bit natural binary code that corresponds to Lb = 212 = 4096 levels, all of which s
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