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Simple 'spring' balance
Punch four holes in an old tin lid with a nail, spacing them partially round the circumference. Pass pieces of string by these holes and tie them together. Now join this scale.
If weights are not available, it is possible to graduate the balance using known volumes of water poured from a calculating jar and by making marks on the supporting stick conflicting the edge of the pan. Stones canthen be found which will give the similar extension and these should be marked for future use as weights. The use of coins for this purpose should also be investigated.
Figure shows an arrangement of a carriage system. A force P is applied on the carriage B and moving rightward at 3 m/s 2 constant acceleration. At the instant shown the velocit
conditions of equilibrium for concurrent force system
The graph shown in Figure was obtained during an experiment on a diode. (a) What type of diode is this? Give reasons. (b) Determine the forward current for a forward voltage
Figure shows the frequency spectrum of a signal at 1184kHz displayed by a high-speed virtual DSO. Determine (a) The harmonic relationship among the signals marked 'o' and 'x',
The spectral lines arising from the transition of electron forms a spectra series. Mainly there are five series and every series is named after it's discover as Lymen series, B
A non uniform rod AB has a mass M and length 2L the mas per unit length of the rod is mx at a point of the rod distant x from A.find the moment of inertia of this rod about an axis
Wave-particle duality: The principle of quantum mechanics that implies that light (and, indeed, all other subatomic particles) sometimes work as a wave, and sometime like a pa
Q Calculate the longest wavelength that can be analysed by a rock salt crystal of spacing d = 2.82 Ao in the first order. Data: d = 2.82 Å = 2.82 × 10-10 m; n = 1 ; λmax = ?
An electron is in a box of width 3*10^-10m.what are de broglies wavlength and magnitude of momentum of the electron if it is in A)n=1 level B)n=2 level C)n=3 level Ans) use the
Total height of the gymnast just before falling back down is=(2+.3)=2.3m Energy gained at that point = m*g*h(m=mass, g=gravitational force, h=height) =55*9.8*2.3=1239.7 J
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