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There is a maximum depth at which a diver can breathe through snorkel tube because as the depth increases, so does the pressure difference, tending to collapse the diver's lungs. Since the snorkel connects the air in the lungs sto the atmosphere at the surface, the pressure inside the lungs is atmospheric pressure. What is the external-internal pressure difference when the diver's lungs are at a depth of 6.1m(about 20ft)? Assume that the diver is in fresh water. (A scuba diver breathing from compressed air tanks can operate at greater depths than can a snorkeler, since the pressure of the air inside the scuba divers lungs increases to match the external pressure of theater.)
What do you mean by a junction diode. Illustrate the formation of depletion layer at the junction. Describe the variation of depletion layer in forward and reverse biased condition
Is there any experiment to tell that water can move from lower concentration to higher Which means flows back to mountain without reversing time Could water flow upward by itself w
A vertical spring generates simple harmonic motion with period 1sec. when a mass of 1gm suspended at the lower end of the spring, calculate the length through which the spring stre
CONSERVATION OF ENERGY 1. Potential energy is, as the word suggests, the energy "locked up" up somewhere and which can perform work. Potential energy Potential energy can b
1. Consider two monoenergetic photon beams with the same photon fluences. In one beam the photons are 100 keV and in the other they are 1 MeV. Determine the most appropriate relati
Demonstrating the cause of the phases of the moon Place a lighted candle or electric lamp on a table in a darkened room. Paint an 8 cm rubber ball white. Hold the ball in your
what is
What are parallel forces?
the two point charges +10 nano coulomb and -20 nano coulomb are seperated by a distance 0.1m. calculate the neutral poiint along the line joining two charges.
Draw the v-t graph of an automobile that accelerates uniformly from rest at t = 0.00 s and covers a distance of 180.0 m in 12.0 s.
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