Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Here are two one-to-one functions f (x ) and g ( x ) if
(f o g )( x ) = x AND ( g o f ) ( x ) = x
then we say that f ( x )& g ( x ) are inverses of each other. More particularly we will say that g ( x ) is the inverse of f ( x ) and specified it by
g ( x ) = f -1 ( x )
Similarly we could also say that f ( x ) is the inverse of g ( x )and specified it by
f (x ) = g -1 ( x )
The notation which we use really based upon the problem. In most of the cases either is acceptable.
For the two functions which we started off this section along with we could write either of the following two sets of notation.
f ( x ) = 3x - 2 f -1(x) = x /3+ 2/3
g ( x ) = x/3 + 2/3 g -1 (x ) = 3x - 2
Now, be careful along with the notation for inverses. The "-1" is not an exponent in spite of the fact that is certain does look like one! While dealing with inverse functions we've got to keep in mind that
f-1(x) ≠ 1/ f ( x )
Example Simplify following logarithms. log 4 ( x 3 y 5 ) Solution Here the instructions may be a little misleading. While we say simplify we actually mean to say tha
46::24
what is -7/2*w=20
log10 (4x100)
I can find what x means I just cant do the interval notation correctly
Mr.Carr is installing wall-to-wall carpeting in a room that measures 12 1/2ft. by 9ft. How much will it cost Mr. Carr if he purchases carpet priced at $26.00 per square yard?
Multiplication?
k^(2-) k-30
the sum of three numbers is 396. what is the second number if the third is number 7 more than the first number and 2 more than the second number?
How do you solve 3(8p-6)+1
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd