Example for Productivity Analysis and Improvement

An excavator with a bucket capacity of 3-yd³ has a standard production rate of 2,160-yd³ for an 8-hour day.  The job site productivity and the actual cycle time of this excavator under the work conditions at the job site that may affect its productivity as shown in the Table, is most nearly:

Solution:  Note that all the factors are less than 1, as such; the job site productivity of the excavator per day is given by:

 P_day = (2,160yds³)(.954)(.983)(.8)(.7)=1,134yds³  

The actual cycle time can be determined as follows: 

T_actual = 40sec/(.954)(.983)(.8)(.7) = 76sec