Evicting pages from physical memory, Operating System

Assignment Help:

When do we write a page from physical memory back to the disk?

In general, caches have two broad types of writing policies. One approach is a write-through cache. In this case, when a value in the cache is written, it is immediately written to the backing store as well (in this case, the disk). The cache and backing store are always synchronized in this case, but this can be very slow. The other main approach is a write-back cache. In this case, the backing store and the cache are sometimes out of sync, but this approach is much faster. This is what is used with paging, for obvious speed reasons.

When a page is loaded from the disk to physical memory, it is initially clean, i.e. the copy in physical memory matches the copy on disk. If the copy in memory is ever changed, then its page-table entry is marked dirty, and it will need to be written back to the disk later. When physical memory ?lls up, and a non-resident page is requested, then the OS needs to select a page to evict, to make room for the new page. The evicted page is called the victim, and is saved to the so-called "swap" space.

The swap space is a separate region of the disk from the ?le system, and the size of the swap space limits the total virtual address space of all programs put together (though in practice, there is a lot of memory shared between processes, for instance shared libraries). There are a variety different strategies for choosing which page to evict, with tradeoffs for each strategy. These strategies will be discussed later. One thing to note is that evicting a clean page is fast, since it doesn't need to be written back to the disk. A second note is that to speed up the process of evicting pages, the OS can write dirty pages back to disk as a background task. In this way, more pages will be clean and can therefore be evicted a lot more quickly, when it is time to do so.


Related Discussions:- Evicting pages from physical memory

Define the scheduling in multitasking, Define the Scheduling in Multitaskin...

Define the Scheduling in Multitasking Earlier we learned the concepts and advantages of multitasking. In a system in which one or more tasks( threads or processes) attempt to s

Define maintaining data on a per client basis, Define Maintaining Data on a...

Define Maintaining Data on a Per Client Basis Perhaps the most dramatic syntactical programming change for the application developer of client – server applications is maintain

Important system components, Organizational, Structural, Logical and Execut...

Organizational, Structural, Logical and Execution Relationships Between Important System Components in Linux Kernel Subsystems A. Description of the Project You are require

Starvation, what do you mean by starvation?explain in detail

what do you mean by starvation?explain in detail

Define i/o and cpu bursts, Define I/O and CPU Bursts   Applications typ...

Define I/O and CPU Bursts   Applications typically to through cycle of CPU bursts and Input/output bursts. Since the CPU sits idle during I/O operations, efficiency is improved

FUNDAMENTAL OF OS, WHAT IS OPERATING SYSTEM ?ENLIST AND EXPLAIN BASIC SERVI...

WHAT IS OPERATING SYSTEM ?ENLIST AND EXPLAIN BASIC SERVICES PROVIDE BY OS

Explain kernel-level threads (klt), KERNEL-LEVEL THREADS (KLT) In this...

KERNEL-LEVEL THREADS (KLT) In this level every thread management is done by kernel .No thread library except an API system calls to the kernel thread facility exists. The kern

Explain producer-consumer problem using semaphores, Producer-Consumer Probl...

Producer-Consumer Problem Using Semaphores The Solution to producer-consumer problem use three semaphores namely- full, empty and mutex. The semaphore 'full' is utilized for

Explain deadlock avoidance, Deadlock Avoidance It's a method to evade ...

Deadlock Avoidance It's a method to evade deadlock by careful resource scheduling. This approach to the deadlock problem foresees deadlock before it actually occurs. This a

Memory organization and decoding, In a  p system each part (RAM, ROM, I/O) ...

In a  p system each part (RAM, ROM, I/O) has a unique set of numbers. The allocation of these numbers is usually stated in the form of a memory map. This is a plot of data bus agai

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd