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Questions:
Regard as two charged particles at a separation of 4 cm. Particle #1 has a charge of +2 micro-coulombs. Particle #2 has a charge of +16 micro-coulombs. How does the magnitude of the force bring to bear on particle #1 beside particle #2 evaluate with the magnitude of the force exerted on particle #2 by particle #1?
Answer:
By Newton's 3rd Law the force that one particle make use of on another particle is equal in magnitude and opposite in direction to the force that the second particle exerts on the first particle. There is no approach around Newton's 3rd law. A particle cannot be pushing on another particle with no that second particle pushing back just as hard. There are no exemptions!
I think it is same as the apex angle of the prism or the angle of the prism. since it decides the angle of deviation as i+e=D+A(angle of the prism),D=deviation.
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octave programing
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