Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
mass=volume * density.By using this formula we can find the mass of sphere.Volume of sphere=(4/3)pi*r^3V=(4/3)*3.14*(1*10^-2)^3=4.187*10^-6Mass=(4.187*10^-6)*900=3768*10^-6kg
how to prepare for logic gate project?
determine the pressure of a 20 lb force applied to an area of 10 inch squared
A car of mass 1600 kilograms (kg) was travelling at 30m/s when the brakes were applied and produced a constant retarding force of 8000 N (Newtons) to the car: Find - a) How far the
define the coefficient of friction
how to you calculate the inducatnce on a balanced delta circuit?
give example phenomena of resonance?
I need some examples (at least 5 examples) of daily life application of vector. could you please help me? thankyou
Reducing friction with ball bearings Find two tin cans that have a deep groove approximately the top, such as paint cans. Lay marbles in single groove and invert the other can
what is zener diode?
the magnetic field at a dictance of 2cm from the axis of a straight conductor carrying current is 12mT.Find the currentin the conductor?
Mass of the sphere is = 4.713 × 10^−4 kg
density = mass/ volumegiven denstiy = 900kg/m3 and diameter = 1cm so radius(R) = 0.5 cm = 0.005m900 = mass/ (4/3 π R3 )Mass = (900*3 π R3 )/4 = (900*3* π *(0.005)3 )/ 4 = 2.650718801×10?4 Kg
radius=0.5cm Volume=4/3pi x (0.5)3 =0.52 cm3 = 0.52 x 10-6 m3 Mass= Density x Volume = 900 x 0.52x10-6 kg =0.468 g
radius=0.5cm
Volume=4/3pi x (0.5)3
=0.52 cm3
= 0.52 x 10-6 m3
Mass= Density x Volume
= 900 x 0.52x10-6 kg
=0.468 g
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd