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Q. A transistor is connected in CE configuration. The voltage drop across the load resistance ( Rc) 3 k is 6 V. Find the base current. The current gain α of the transistor is 0.97.
The voltage drop across the load resistance = ICRC = 6V
IC = 6 / Rc = 6 / 3 X 103 = 2 mA.
β = α / 1-α = 0.97 / 1 -0.97 = 32.33
I B = I C / β = 2 X 10 -3 / 32.33
= 61.86 μA
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