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In this section we are going to look at equations which are called quadratic in form or reducible to quadratic in form. What it means is that we will be looking at equations that if we look at them in the accurate light we can make them look like quadratic equations. At that point we can employ the techniques we developed for quadratic equations to help us with the solution of the actual equation.
Usually it is best with these to demonstrate the procedure with an example so let's do that.
(7x^3+6x^2)-2 -7x^3+6x^2-2 did I solve this correctly
3x+5y=10
Solve out the following system of equations by using augmented matrices. 3x - 3 y - 6 z = -3 2x - 2 y - 4 z = 10 -2x + 3 y + z = 7 Solution Following is the au
Harold’s movie theater increased the price of admission 20%. Tickets had sold for $7.00. What is the current ticket price? Percent of Decrease: 3. Original Price: $45
Example : Use the quadratic formula to solve following equation. x 2 + 2x = 7 Solution Here the important part is to ensure that before we b
??2+??2+16??-18??+145=25 Standard form (x-h)^2 +(y-k)^2 k (x^2+16x+64)^2+(y^2-18y+81)^2=25 (x+8)^2+(y-9)^2=120 (h,k)=(8,-9) R=5 Intercepts
Example: Solve following equations. 2 log 9 (√x) - log 9 (6x -1) = 0 Solution Along with this equation there are two logarithms only in the equation thus it's easy t
f(2)=3 and g(x)=x^2+1 then gof(2)
wqdweq wqre
2.3*10^3,3.7*10^2,6.5*10^3
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