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In this section we are going to look at equations which are called quadratic in form or reducible to quadratic in form. What it means is that we will be looking at equations that if we look at them in the accurate light we can make them look like quadratic equations. At that point we can employ the techniques we developed for quadratic equations to help us with the solution of the actual equation.
Usually it is best with these to demonstrate the procedure with an example so let's do that.
-4/-1-4/+6
If a firm sellings its product at a price $p per unit, customers would buy q units per day where q = 1,350 - p. The cost of producing q units per day is $C(q) where C(q) = 50q + 36
How did they get an answer of 4.24899(-6) the question isc=4d(-1)/3.b. I now i substitute 23,245 for d and 13.5 for b, but don''t understand how they got this answer?
In the earlier section we looked at using factoring & the square root property to solve out quadratic equations. The problem is that both of these methods will not always work. Not
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Example Solve following systems. (a) 3x - y = 7 2x + 3 y = 1 Solution Thus, it was the first system that we looked at above. Already we know th
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Perpendicular to y=3x-2 and through the point (6,4)
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