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In this section we are going to look at equations which are called quadratic in form or reducible to quadratic in form. What it means is that we will be looking at equations that if we look at them in the accurate light we can make them look like quadratic equations. At that point we can employ the techniques we developed for quadratic equations to help us with the solution of the actual equation.
Usually it is best with these to demonstrate the procedure with an example so let's do that.
lt
An inlet pipe can fill a large water tank in 4 hours. Another inlet pipe can fill the same water tank in 5 hours. Given an empty water tank, at 8:00 AM, activate both pipes. What t
3u^3-5u^2-2u=0
how to do this problem using quadratic formula to solve the equation 2xexpont 2 minus 9x equals 1
the perimeter of a triangle is 76 centimeters. the second side is twice as long as the first side. the third side is four centimeters shorter then the second side. how long is each
r+7= r=3
-6k+7k=
50P3
To this instance in this chapter we've concentrated on solving out equations. Now it is time to switch gears a little & begin thinking regarding solving inequalities. Before we g
f(x)=-12x^2-24x+7
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