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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
my son is in middle school and his teacher pre-algebra teacher wants him to write a summary on "who I am " about his self. summary about myself. I need your to know do have a any
let x,y,z be the complex number such that x+y+z=2,x^2+y^2+z^=3,x*y*z=4,then 1/(x*y+z-1)+1/(x*z+y-1)+1/(y*z+x-1) is
Ask question #15/16 to the percentage
a 9f2 square painting is mounted with border on a square frame. if the total area of the border is 3.25 ft2, what is the length of a side of the frame?
so I''m having trouble. I honestly don''t under stand this. Y=4x+5. y=-1/4x+4 they want me to tell whether the line is parallel, perpendicular or neither I don''t know how.
Some of the grouping symbols are braces,brackets,and parentheses.
how can we solve if the given is negative?
can u show me how to solve this (5x+14)-(3x-5)
How do you do out a substitution problem and then graph it?
x+y=5 Y+-2x+5
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