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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
in her last gymnastics competition Keri scored a 5.6 on the floor exercise, 5.85 on the vault and 5.90 on the balance beam. what was keri''s total?
solve x+4y=8 2x+5y=7
1. f(x)=-2x+7x^2
a circular flower bed has radius 22 inches. what is the circumference of the bed to the nearest tenth of an inch?
1). Using the function: y=y0,(.90)^t-1. In this equation y0 is the amount of initial dose and y is the amount of medication still available t hours after drug is administered. Supp
What is the effectiveness of new math?
2-1-f+7=
#question ..
Next we desire to take a look at f (x ) =√x . First, note that as we don't desire to get complex numbers out of a function evaluation we ought to limit the values of x that we can
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