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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
2.3*10^3,3.7*10^2,6.5*10^3
c/6 - 1/2 = 3
hello! at my school we are learning how to solve two-step equations but i am having a little trouble. can you please help me?
Solve 2 x 10 - x 5 - 4 = 0 . Solution We can reduce this to quadratic in form using the substitution, u = x 5 u 2 = x 10 By using this substitution the equa
what is a word problem for a nonlinear function?
We desire to look at the graph of quadratic function. The most general form of a quadratic function is, f (x ) = ax 2 + bx
can u show me how to solve this (5x+14)-(3x-5)
ue Week 7 and worth 55 points Five (5) years ago, you bought a house for $171,000, with a down payment of $30,000, which meant you took out a loan for $141,000. Your interest rate
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I do not understand graphing at all.
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