Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Elementary Induction Machines
In the discussion that followed Equation, the third possiblemethod of producing constant torque was to cause the mmf axes of stator and rotor to rotate at such speeds relative to their windings that they remain stationary with respect to each other. If the stator and rotor windings are polyphase and carry polyphase alternating current, then both the stator mmf and the rotor mmf axes may be caused to rotate relative to their windings. Such a machine will have polyphase stator ac excitation at ωs , polyphase rotor ac excitation at ωr , and the rotor speed ωm satisfying
ωm = ωs - ωr
Let us consider the rotor speed given by Equation and the same phase sequence of sources. A rotating magnetic field of constant amplitude, rotating at ωs rad/s relative to the stator, is produced because of polyphase stator excitation. A rotating magnetic field of constant amplitude, rotating at ωs rad/s relative to the rotor, is also produced because of polyphase rotor excitation. The speed of rotation of the rotor magnetic field relative to the stator is ωm + ωr ,or ωs , if the rotor is rotating with a positive speed of rotation ωm in the direction of the rotating fields. If so, the condition for energy conversion at constant torque is satisfied. Such a situation is illustrated diagrammatically in Figure. Under these conditions the machine is operating as a double-fed polyphase machine. Normally, in an induction machine with polyphase stator and rotor windings, only a source to excite the stator is employed, and the rotor excitation at the appropriate frequency is induced from the stator winding. The device is thus known as an induction machine.
what is one common applicable for CB amplifier
material to produce analog oscilloscope
Error-Rate Control, Output-Rate Control, and Integral-Error (Reset) Control Let us consider a typical second-order servomechanism(containing two energy-storing elements) whose
A circular ring of magnetic material has a mean length of 1m and a cross sectional area of .001m^2.A sawcut of 5mm width is made in the ring . calculate the magnetizing current req
1. A modi?ed NRZ code known as enhanced-NRZ (E-NRZ) operates on 7-bit words; invert- ing bits 2,3,6 and 7; and adding one parity bit to each word. The parity bit is chosen to make
equilizing connection
Applications of Hall Effect: (i) To determine whether semiconductor is of n type or p type. (ii) To determine carrier concentration. (iii) Measurement of carrier mobili
Question: a). Draw the energy diagram of a pn junction: (i) at thermal equilibrium, (ii) when a forward bias with magnitude half the built in potential (V = φk/2) is applie
What do you understand by orthographic projection ? Illustrate with the help of Matrix representation.
explain speed control of dc motor
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd