Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Effects of NULL Operator
As a general rule-but not a universal one-if NULL is an argument to an invocation of a system-defined read-only operator, then NULL is the result of that invocation. As you can see, the code for HIGHER_OF includes A > B, an invocation of the system-defined read-only operator ">", which does follow the general rule. Hence, if NULL is substituted for either or both of the parameters A and B, then NULL- which in this case we can also call UNKNOWN because ">" is a Boolean operator-is the result of the invocation. You are perhaps now wondering how SQL handles the IF statement when the specified condition yields UNKNOWN: is the THEN clause evaluated, or is it the ELSE clause?
As you know, other programming languages are normally based on classical logic. In keeping with the existence of just two truth values, TRUE and FALSE, the syntax for IF statements (and IF expressions) in such languages has just the two forks, THEN for when the condition is TRUE, ELSE for when it is not (i.e., is FALSE). You might therefore reasonably expect a language that embraces n truth values to support a variety of IF that has n forks-under a language design principle that Fred Brooks referred to as conceptual integrity, which means adhering rigorously to the language's adopted concepts. Instead, SQL retains just the two forks, keeping the normal treatment of THEN as being the one for when the condition is TRUE and arbitrarily lumping UNKNOWN in with FALSE for the ELSE fork. You should now be able to see that the general rule ("NULL in, NULL out") for system-defined operators cannot be said to apply to user-defined ones. If A > B evaluates to UNKNOWN, then the result of the HIGHER_OF invocation is the argument substituted for B, which might or might not be NULL.
Question: Consider the following relations (primary keys are underlined): AUTHOR (ANo, aname, address, speciality) PUBLISHER (PNo, pname, Location) BOOK (BNo, Title, ISBN,
Using a join on 2 tables, select all columns and 10 rows from the 2 tables without the use of a Cartesian product. Query: SELECT * FROM EMPLOYEE1 E JOIN STAFF S ON E.EMP_
Constants and Variables: You can declare the constants and variables in the declarative section of any PL/SQL subprogram, block, or package. The Declarations allot the stor
Oracle 11 G new features associated with this release:- Enhanced ILM - Information Lifecycle Management (ILM) has been around for the almost 10 years, but Oracle has made
Object Type: The object type is a user-defined composite datatype which encapsulates a data structure along with the functions and procedures required to manipulate the data
I need SQL Data Base Project Description: Network SQL database and SQL Setup two 4 workstation Skills required are Data Entry, MySQL, SQL
different lock modes used in the locking system
Explicitly specifying the join condition - SQL SELECT * FROM IS_CALLED JOIN IS_ENROLLED_ON ON ( IS_CALLED.StudentId = IS_ENROLLED_ON.StudentId ) Now, the key word JO
#quesWrite a cursor to open an employee database and fetch the employee record whose age is greater than 45.tion..
Example of ADD CONSTRAINT in SQL Example: Alternative formulation for MAX_ENROLMENTS ALTER TABLE IS_ENROLLED_ON ADD CONSTRAINT MAX_ENROLMENTS CHECK ((SELECT COUNT (*)
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd