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If e were rational, then e = n/m for some positive integers m, n. So then 1/e = m/n. But the series expansion for 1/e is
1/e = 1 - 1/1! + 1/2! - 1/3! + ...
Call the first n values of this alternating series S(n). How good is this approximation to e? Well, the error is bounded by the next part of the alternating series:
0 < | 1/e - S(n) | = | m/n - S(n)| < 1/(n+1)!
But multiplying through by n!, you can see that
0 < | integer - integer | < 1/(n+1) < 1.
But there is no integer between 0 and 1, so this is a contradiction; e must be irrational.
0/2
Logarithmic functions have the following general properties If y = log a x, a > 0 and a ≠1, then The domain of the function
who,why and when discover
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y=9x-5x+2 and y=4+12
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