Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Carry out the indicated operation and dropped down the answer to lowest terms.
(x2 - 5x -14/ x2-3x+2) . (x2 - 4)/x2-14x+49)
Solution
This is a multiplication. The first thing that we have to always do in the multiplication is to factor everything into sight as much as possible.
(x2 - 5x -14/ x2-3x+2) . (x2 - 4)/x2-14x+49)=((x-7)(x+2)/(x-2)(x-1)).((x-2)(x+2)/(x-7)2)
Now, recall that we can cancel out things across a multiplication like this.
Note that it only works for multiplication and NOT for division!
In this case we do have multiplication hence cancel as much as we can and then do the multiplication to acquire the answer.
(x2 - 5x -14/ x2-3x+2) . (x2 - 4)/x2-14x+49)= (x+2) /( (x-1). (x+2) (x-7) = (x+2)2 /(x-1). (x-7)
(3+x)(3-x)
Jay bought twenty-five $0.37 stamps. How much did he spend? To ?nd how much Jay spent, you must multiply the cost of each stamp ($0.37) through the number of stamps purchased (
80 divide by 3
If r,R denote position vectors of points on the straight lines in the direction of a and b respectively, and if n is a unit vector perpendicular to both these directions, show that
-9/5 / 2
1
Standard Basis Vectors Revisited In the preceding section we introduced the idea of standard basis vectors with no really discussing why they were significant. We can now do
mulply # fraction
41x + 53y = 135, 53x +41y =147 Ans: 41x + 53 y = 135, 53 x + 41 y = 147 Add the two equations : Solve it, to get ... x + y = 3 -------(1) Subtract : Solve it , to
JUST IS WHOLE
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd