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Find (dy)/( dx) for;
(i). y = x7
(ii). y = x2γ
(iii). y = x-3
(iv). y = x
what are the parts of angles
14/3
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solve for k such that the system 4x+ky=6 kx+y=-3
Solution i. y = x7 (dy)/( dx) = 7x 7-1 = 7x6 ii. y = x2? (dy)/(dx) = 2γ x(2γ- 1) iii. y = x-3 (dy)/(dx) = -3x-3-1 = -3x-4 vi. y = x (dy)/( dx) = 1x1-1 = 1.x0= 1 (since x0=1)
Solution
i. y = x7
(dy)/( dx) = 7x 7-1 = 7x6
ii. y = x2?
(dy)/(dx) = 2γ x(2γ- 1)
iii. y = x-3
(dy)/(dx) = -3x-3-1 = -3x-4
vi. y = x
(dy)/( dx) = 1x1-1 = 1.x0= 1 (since x0=1)
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