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Differentiate OO development from structured development.
Structured approach of problem solving is based upon the idea of decomposition of system into subsystem. In this approach of system development, readjustment of some new changes in system is very hard. While as in object oriented approach holistic view of application domain is considered and the related objects are identified. Further categorization of objects is done. Object oriented approach provide space for further enhancement of system without too much increase in the systems complexity.
Ask questioYou are the database administrator in a university. You have been tasked to come up with a new database for the University. Using the stages in Database Life Cycle come
Explain the terms primary key, candidate key, alternate key and secondary key. In the given table identify every key? STUDENT(SID,Regno, Name, City) Primary Key: The prim
Provide Examples of different types of Time and Date formats. It's most common store dates using a dash (-) as a colon (:)and the delimiter as the time delimiter. The given fo
Ask question #Minim 100 words accepted#what is recovery management component in database management system and how it is useful
Explain Recursive relationship type? Recursive relationship type: A recursive relationship is one in that the similar entity participates more than once in the relationship
Which database object does not physically exist? A view database object does not physically exist.
What is Object Oriented model? This model is based on collection of objects. An object has values stored in instance variables with in the object. An object also having bodies
Compare wait-die deadlock prevention scheme with wait-wound scheme Ans: Wait-Die Scheme a) Based upon a nonpreemptive technique. b) If Pi requests a resource present
Aggregate functions Some of these functions are min, count, max, and avg. These functions help in getting consolidated information from a set of tuples. Example:
Concatenation operator Example : Printing name and job as one string as column name employees: SELECT ENAME||JOB "EMPLOYEES" FROM EMP;
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