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Differentiate following functions.
h (t ) = 2t5 + t2- 5 / t2
We can simplify this rational expression as follows.
h (t ) = 2t5 / t2+ t2 / t2 - 5 / t2 = 2t 3 + 1 - 5t -2
It is a function which we can differentiate.
h′ (t ) = 6t 2 ++ 10t -3
Fermat's Theorem If f(x) has a relative extrema at x = c and f′(c) exists then x = c is a critical point of f(x). Actually, this will be a critical point that f′(c) =0.
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One-sided limits: We do this along with one-sided limits. As the name implies, with one-sided limits we will just looking at one side of the point in question. Following are the
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