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Differentiate following functions.
h (t ) = 2t5 + t2- 5 / t2
We can simplify this rational expression as follows.
h (t ) = 2t5 / t2+ t2 / t2 - 5 / t2 = 2t 3 + 1 - 5t -2
It is a function which we can differentiate.
h′ (t ) = 6t 2 ++ 10t -3
Solve -10 cos(3t )= 7 on [-2,5]. Solution Let's first get the inverse cosine portion of this problem taken care of. cos(3 t )= - 7/10 ⇒ 3t = cos -1 ( - 7
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