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An insurance company/organization takes a keen interest in the age at which a person is insured. Thus a survey conducted on prospective clients indicated that for clients having the similar age the probability that they will be alive in 30 years time. This probability was established by utilizing the actuarial tables. If a sample of 5 people was insured still, determine the probability of having the given possible outcomes in 30 years
a) All are alive
b) At least 3 are alive
c) Mostly one is alive
d) None is alive
e) At least 1 is alive
Sample size = 5
P(alive) p = 2/3 where P (not alive) = q = 1/3
If 7sin 2 ?+3cos 2 ? = 4, show that tan? = 1/√3 . Ans: If 7 Sin 2 ? + 3 Cos 2 ? = 4 S.T. Tan? 1/√3 7 Sin 2 ? + 3 Cos 2 ? = 4 (Sin 2 ? + Cos 2 ?)
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Find out some solutions to y′′ - 9 y = 0 Solution We can find some solutions here simply through inspection. We require functions whose second derivative is 9 times the
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Utilizes the definition of the limit to prove the given limit. Solution Let M > 0 be any number and we'll have to choose a δ > 0 so that, 1/ x 2 > M
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Find the middle term of the AP 1, 8, 15....505. A ns: Middle terms a + (n-1)d = 505 a + (n-1)7 = 505 n - 1 = 504/7 n = 73 ∴ 37th term is middle term a 37
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