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The height of a rectangle is 20 cm. The diagonal is 8 cm more than the length. Determine the length of the rectangle.
a. 20
b. 23
c. 22
d. 21
d. To determine the length of the rectangle, we will use the Pythagorean theorem. The width, a, is 20. The diagonal, c, is x + 8. The length, b, is x; a2 + b2 = c2; 202 + x2 = (x + 8)2. After multiplying the two binomials (using FOIL), 400 + x2 = x2 + 16x + 64. Subtract x2 from both sides; 400 = 16x + 64. Subtract 64 from both sides; 336 = 16x. Divide both sides by 16; 21 = x. If you select a, you incorrectly calculated the diagonal to be 28.
Find the value of x if 2x + 1, x 2 + x +1, 3 x 2 - 3 x +3 are consecutive terms of an AP. Ans: a 2 -a 1 = a 3 -a 2 ⇒ x 2 + x + 1-2 x - 1 = 3x 2 - 3x + 3- x
How the property AM>or = GM used to get minimum value of the function......e,g for what condition of a and b does minimum value of a tan^2 x + b cot^2 x equals maximum value of a
20348876567
Example Reduce 24/36 to its lowest terms. 24/36=12/18=6/9=2/3. In the first step we divide the numerator and the denominator by 2. The fraction gets reduced
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The length of the sides of a triangle are 2x + y/2 , 5 x/3 + y + 1/2 and 2/3 x + 2y + 5/2. If the triangle is equilateral. Find its perimeter. A ns: 2x + y/2 = 4x + y
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