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Solve sin (3t ) = 2 .
Solution
This example is designed to remind you of certain properties about sine and cosine. Recall that -1 ≤ sin (θ ) ≤ 1 and -1 ≤ cos(θ ) ≤ 1 . Thus, as sine will never be greater that 1 it definitely can't be two. Hence THERE ARE NO SOLUTIONS to this equation!
It is significant to remember that not all trig equations will have solutions.
Solve 9 sin ( 2 x )= -5 cos(2x ) on[-10,0]. Solution At first glance this problem appears to be at odds with the sentence preceding the example. However, it really isn't.
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Proof of: if f(x) > g(x) for a x b then a ∫ b f(x) dx > g(x). Because we get f(x) ≥ g(x) then we knows that f(x) - g(x) ≥ 0 on a ≤ x ≤ b and therefore by Prop
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