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Solve sin (3t ) = 2 .
Solution
This example is designed to remind you of certain properties about sine and cosine. Recall that -1 ≤ sin (θ ) ≤ 1 and -1 ≤ cos(θ ) ≤ 1 . Thus, as sine will never be greater that 1 it definitely can't be two. Hence THERE ARE NO SOLUTIONS to this equation!
It is significant to remember that not all trig equations will have solutions.
verify liouville''s theorem for y''''''-y''''-y''+y=0
Express the product of -9p3r and the quantity 2p - 3r in simplified form. The translated expression would be -9p3r(2p - 3r). Noticed that the key word product means multiply.
-2-1
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