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Solve sin (3t ) = 2 .
Solution
This example is designed to remind you of certain properties about sine and cosine. Recall that -1 ≤ sin (θ ) ≤ 1 and -1 ≤ cos(θ ) ≤ 1 . Thus, as sine will never be greater that 1 it definitely can't be two. Hence THERE ARE NO SOLUTIONS to this equation!
It is significant to remember that not all trig equations will have solutions.
Proof of: lim q →0 (cos q -1) / q = 0 We will begin by doing the following, lim q →0 (cosq -1)/q = lim q →0 ((cosq - 1)(cosq + 1))/(q (cosq + 1)) = lim q
what are these all about and could i have some examples of them please
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