Determine the forces in strings:

The Electric light fixture weighing 15N hangs from point C, by two strings AC and BC. AC is inclined at 60° to the horizontal and BC at 45° to the vertical as shown in figure given below, Determine the forces in strings AC and BC

Sol.: First draw the free body digram of the electric light fixture, Apply lami's theorem at 'C'

T₁/sin 150° = T2/sin 135° = 15/sin75°

T₁ = 15.sin150°/ sin75°

T₁ = 7.76N                                                     .......ANS

T₂ = 15.sin135°/ sin75°

T₂ = 10.98N                                                  .......ANS