Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Determine the final temperature in piston – cylinder:
One Kg of steam at 1.5MPa and 400ºC in a piston - cylinder device is cooled at constant pressure. Determine the final temperature and change in volume. If cooling continues till the condensation of 2/3 of the mass.
Sol.: Given that
Mass of steam m = 1kg
Pressure of steam P1 = 1.5MPa = 15bar
Temperature of steam T1 = 400ºC From superheated steam table
At P1 = 15bar, T1 = 400ºC Å1 = 0.1324m3/kg
Å2 = (2 x 0.1324)/3 = 0.0882m3/kg
Change in volume "Å = Å1 - Å2 = 0.1324 - 0.0882 = 0.0441m3/kg
The steam is wet at 15bar; thus, the temperature will be 198.32ºC.
Q. What is IFD in project management? The P&IDs now reflect the next intermediate stage of development and incorporate any changes requested by the Customer during the IFA revi
The de-oiled water from De-Oiling Unit enters the HLS vessel for softening. The primary function of HLS is to remove the Ca and Mg hardness and bring the total hardness to less tha
what is the difference between atomic structure and crystal structure
Method of section: Define the method of section? How can you solve the problems with the help of method of section? Sol.: This method is powerful method for determining
Find out bulk modulus: A steel bar of 25 mm diameter was tested on a gauge length of 250 cm in tension and in torsion. A tensile load of 50 kN generated an extension of 0.13 m
Q. Explain about Postweld Heat Treatment? Pressure vessels shall be postweld heat treated per applicable sections, in accordance with applicable material specifications or when
Consider a car of mass m1 is towing a trailer of mass m2 through a tow bar of stiffness k. Drag forces proportional to the car velocity (b1 v1) and the trailer velocity (b2 v2) a
Give differences between direct stress and bending stress. Direct tensile and compressive stress is set up because of load applied parallel to length of object, and direct shea
I was wondering if anyone could help me design an aid for my pet rat that has hind leg degeneration. I have a long slope where i can train him to climb on some kind of trolley and
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd