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Determine the equivalent winding resistance:
A 50 kVA, 2200/110 V, 50 HZ' transformer contain an HV winding resistance of 0.15 Ω and a leakage reactance of 0.45 Ω. The LV winding contain a resistance of 0.006 Ω and a leakage reactance of 0.012 Ω. Determine the equivalent winding resistance, reactance and impedance referred to the HV and LV sides.
Solution
Z'1 = r1 + j x1 = 0.15 + j 0.45
Z'2 = r2 + j x2 = 0.006 + j 0.012
Z' (HV ) = Z'1 + Z'2′
Z'2′ = ( 2200 )2 /110 (0.006 + j 0.012) = (2.4 + j 4.8) Ω
Z'(HV ) = (0.15 + j 0.45) + (2.4 + j 4.8) = (2.55 + j 5.25) Ω
Likewise
Z' (LV ) = Z'1′ + Z'2
= (110 /2200)2 (0.15 + j 0.45) + (0.006 + j 0.012) Ω
= (0.006375 + j 0.01312) Ω
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