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The generator of AM EMFs consists of a battery-driven radiofrequency (RF) EMF generator connected to a 1.5 m long 50 ? coaxial cable, to the other end of which a stainless-steel spoon-shaped mouthpiece is connected via an impedance transformer. The RF source of the device corresponds to a class C amplifier operating at 27.12 MHz. The carrier frequency is AM with a modulation depth of 85±5%, whereas the modulation frequency is generated by a digital direct synthesiser with a resolution of 10-7. The treatment sequence is controlled by a microcontroller (Atmel AT89S8252, Fribourg, Switzerland), that is, duration of session, sequence of modulation frequencies and duration of each sequence can be programmed via PC over a RS232 interface. The RF output is adjusted to 100 mW into a 50 ? load, which results in an emitting power identical to that of the device used for the treatment of insomnia.
what is power system Analysis
Q. Show Transformer equivalent circuits? Transformers come in various sizes, from very small, weighing only a few ounces, to very large, weighing hundreds of tons. The ratings
Q. Give applications of emitter follower The emitter follower has the following principal applications: 1. To provide current amplification with no voltage gain 2. Impede
If aluminium and copper pipes are of same length and diameter ... same magnet dropped through them...in copper it takes more time to come out of other end, i myself have done this.
tension and sag problems
component rating
cosider a causal LTI system whose system function is H(z)=1-1/5z^-1/(1-1/2z^-1+1/3z^-2)(1+1/4z^-1) find the direct form 1 and direct form 2
Q. What do you mean by Binary Multiplication? The Rules of Binary Multiplication 0 x 0 = 0 0 x 1 = 0 1 x 0 = 0 1 x 1 = 1 , and no carry or borrow
Q. Describe the following phasor equations represented in the time domain: (a) ¯ E = K1e-¯ γz (b) ¯ E = K2e ¯ γz where z is the space coordinate, K1 and K2 are constants,
Int r insic Material A perfect semiconductor crystal with no impurities or lattice defects. No carriers at 0 K, since the valence band is completely full and t
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