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Q. A transistor is connected in common emitter configuration collector supply voltage Vcc is 10 volts load resistance Rl is 800ohm,voltage drop across load resistance is 0.8v and current gain I=0.96. Determine collector - emitter voltage and base current?
Collector voltage supply Vcc = 10V
Voltage drop across load resistance IcRl = 0.8V
Collector emitter voltage Vce = Vcc-IcRl = 10-0.8=9.2
Collector current ,Ic=IcRL/RL = 0.8/800=1.0mA
Collector gain factor ,?= I/(1- I) = 0.96/(1-0.96) = 24
Forward Voltage Triggering If V a is increased the collector to emitter voltages of both transistor are also increased. Hence the leakage current at J 2 increase. This
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