A certain memory has a capacity of 4K × 8
(i)  How many data input and data output lines does it have?
(ii) How many address lines does it have?
(iii) What is its capacity in bytes?

Ans.

(i) available capacity =4Kx8
= 2¹⁰ x2¹⁰ x 8
= 2¹²x8
Since in the 4Kx8 ,the second number shows the number of bits in each word therefore the number of data input lines will be 8 and also the data output lines.
(ii) That has total 4K (2¹²) address line that are required to address 2¹²  locations.
(iii) Capacity in bytes of this is 4K bytes.