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A certain memory has a capacity of 4K × 8(i) How many data input and data output lines does it have?(ii) How many address lines does it have?(iii) What is its capacity in bytes?Ans.
(i) available capacity =4Kx8= 210 x210 x 8= 212x8Since in the 4Kx8 ,the second number shows the number of bits in each word therefore the number of data input lines will be 8 and also the data output lines.(ii) That has total 4K (212) address line that are required to address 212 locations.(iii) Capacity in bytes of this is 4K bytes.
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