Design a mod-6 synchronous counter, Computer Engineering

Assignment Help:

Design a MOD-6 synchronous counter using J-K Flip-Flops.

Ans:

Design of Mod-6 Counter:  To design the Mod-6 synchronous counter, contain six counter states (that is, from 0 to 6). For this counter, the counter design table lists the three flip-flop and their states as 0 to 6 and the 6 inputs for the 3 flip-flops. The flip-flop inputs essential to step up the counter from the now to the next state is worked out along with the help of the excitation table.  The needed counter states and the J K inputs essential for counter flip- flops are specified in the counter design table demonstrated in Table no.1.

Input pulse

 

count

Counter States

 

Flip-Flop Inputs

 

A          B          C

 

JA

 

       KA

 

JB                KB

 

JC                  KC

0

0           0          0

1             X

0                 X

0                    X

1

1           0          0

X             1

1                 X

0                    X

2

0           1          0

1             X

X                 0

0                    X

3

1           1          0

X             1

X                 1

1                    X

4

0           0          1

1             X

0                 X

X                    0

5

1           0          1

X              1

0                 X

X                    1

6(0)

0           0         0

 

 

 

Table no.1: Counters Design Table for Mod-6 Counter

 Flip-Flop A:

The primary state is 0. This change to 1 after the clock pulses. Thus, JA must be 1 and KA may be 0 or 1 (that is X). In the subsequent state 1 change to 0 after the clock pulse.  Hence, JA may be 0 or 1 (that is, X) and KA must be 1.

Flip-Flop B:

The primary state is 0 and this remains unchanged after the clock pulse. Hence, JB   must be 0 and KB may be 0 or 1 (i.e. X). In the subsequent state 0 changes to 1 after the clock pulse. Hence, JB must be 1 and KB may be 0 or 1 (that is, X).

Flip-Flop C:

The primary state is 0 and this remains unchanged after the clock pulse. Hence JC must be 0 and KC may be 0 or 1 (that is, X). In the subsequent state, this remains unchanged after the clock pulse. Thus, JC must be 0 and KC may be 0 or 1 (that is, X).The JK inputs needed for such have been found with the help of the excitation table, (as in table no.1). The flip-flop input values are entered into Karnaugh maps demonstrated in Fig. a [(i), (ii), (iii), (iv), (v) and (vi)] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. As all the counter states have not been utilized, Xs (don't) are entered to denote un-utilized states. The expressions that simplified for each input have been demonstrated under each map. At last, these minimal expressions for the flip-flop inputs are utilized to draw a logic diagram for the counter demonstrated in fig.(b).

As before, the JK inputs needed for this have been found with the help of the excitation table, (as in table no.1). Such input values are entered in Karnaugh maps Fig. (a)[i to vi] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. Xs have been entered in that counter states that have not been utilized. The simplified expressions for all inputs have been demonstrated under each map and at last a logic diagram based upon these expressions is drawn and is demonstrated in fig.(b).

983_Karnaugh Maps for JA,KA,JB,KB,JC,KC.png

1325_Karnaugh Maps for JA,KA,JB,KB,JC,KC1.png

Fig.(b) Karnaugh Maps for JA,KA,JB,KB,JC,KC

1472_Logic Diagram for MOD-6 Synchronous Counter.png

Fig.(c) Logic Diagram for MOD-6 Synchronous Counter


Related Discussions:- Design a mod-6 synchronous counter

Implement simplified expression using nor gates only, Q. For function F(x,y...

Q. For function F(x,y,z) = ∑m (1,2,3,5,6) using TRUTH TABLE only 1. Find POS expression 2. Implement this simplified expression using two level OR-to-AND gate network 3. I

What are the update types possible, What are the update types possible? ...

What are the update types possible? The following update types are possible: Update type A: The matchcode data is updated asynchronously to database changes. Update

How do subroutines help in program writing, How do subroutines help in prog...

How do subroutines help in program writing? Some of the significant characteristics of Subroutine that help in program writing are: A subroutine is named, each have a

Explain the fixed logic versus programmable logic, Explain the Fixed Logic ...

Explain the Fixed Logic Versus Programmable Logic? The Logic devices can be classified into two broad categories - fixed and programmable. The same as the name suggests, the ci

What are the uses of interactive reporting, What are the uses of interactiv...

What are the uses of interactive reporting? The user can actively control data retrieval and show during the session.  Instead of an extensive and detailed list, you make a ba

Write a program to find 2''s complement of a binary number, Q. Write a pro...

Q. Write a program to find 1's and 2's complement of a Binary number. Perform necessary checking that if entered number is not a valid number, ask user to enter valid Binary n

What is one-way association, What is one-way association? One-way assoc...

What is one-way association? One-way association means association will traverse in only in one direction and implement using the actual implementation. If the multiplicity is

Truth tables - artificial intelligence, Truth Tables - artificial intellige...

Truth Tables - artificial intelligence: In propositional logic, where we are limited to expressing sentences where propositions are true or false - we can check whether a speci

What do you mean by execution unit, Q. What do you mean by Execution Unit? ...

Q. What do you mean by Execution Unit? Execution unit performs all ALU operations. Execution unit of 8086 is of 16 bits. It also contains the control unit that instructs bus in

Routines which handle dynamic processes, Q. Routines which handle dynamic p...

Q. Routines which handle dynamic processes? number of routines which handle dynamic processes:  int pvm_joingroup( char *group ) Enrolls calling process in a na

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd