Design a doubly linked list, Data Structure & Algorithms

Assignment Help:

Instructions :

  • You have to design a doubly linked list container.
  • The necessary classes and their declarations are given below
  • The main() function for testing the your design is also given below. The outputs form each of the output statements are provided in the text box for your comparison.
  • So complete the program by supplying your implementations of the member functions. Some are already implemented, use as it is.

// List . h

template

class List;

template

std::ostream& operator<< (std::ostream& os, const List& l);

template

class Link;

template

class ListIterator;

template

class List{

            friend std::ostream& operator<< (std::ostream& os, const List& l);

public:

typedef ListIterator Iterator;

List() : first_(0), last_(0) {};

List(const List & other);                    // copy constructor

~List();                                                  // destructor

List & operator = (const List & rhs);  // assignment operator

T& front() const;                                                // returns the front element

void push_front(const T& e);                  // adds from front

void pop_front();                                               // deletes from front

T& back() const;                                                // returns the last element

void push_back(const T& e);                 // adds from back

void pop_back();                                               // deletes the last element

void clear();                                                       // emptied by deleting all elements in it

bool empty() const;                                           // return true if list id empty

int size() const;                                      // returns the no. of elements

Iterator begin();

Iterator end();

Iterator insert(Iterator& itr, const T& val);

void insert(Iterator& itr, int n, const T& val);

void erase(Iterator& itr);

void erase(Iterator& start, Iterator& stop);

private:

void copy(const List & other);                      // private utility only, users use =

Node* first;                                     // points to first node

Node* last;                                      // points to last node

};

template

std::ostream& operator<< (std::ostream& os, const List& lst){

            os<<"f[ ";

            Link *pp = lst.first_; //cursor to lst

            while(pp != 0){

                        if(pp != lst.first_)os<<", ";

                                    os<< pp->elem_;

                        pp = pp->next_;

            }

            os<<" ]b"<

            return os;

}

 

template                                 //  implements the node of a doubly linked list

class Node{

                        friend class List;

                        friend class ListIterator;

                        friend std::ostream& operator<< (std::ostream& os, const List& l);

            private:

                        Node(const T& e) : elem_(e), next_(0), prev_(0){} // constrructor

                        T elem_;                        // element value

                        Node* next; //  pointer to next element in the list

                        Node* prev; //  pointer to the previous element in the list

};

template                                 // implements a iterator for the list class

class ListIterator{

                        friend class List;

                        typedef ListIterator Iterator;

            public:

                        ListIterator(List* list = 0, Link* ccNode = 0) : list_(list), cNode(ccNode) {}

                        T& operator *(){

                                    //  returns the element value of the node pointed by the iterator

                        }

                        bool operator == (Iterator rhs){

                                    // returns true  if this integrator and itertrator rhs are pointing to same node                                  }

                        bool operator != (Iterator rhs){

                                    // returns false if this integrator and itertrator rhs are pointing to same node        

                        }

                        Iterator& operator ++ (int){

                                    // advance the iterator to the right

                        }

                        Iterator operator ++ (){

                                    // postfix version

                        }

                        Iterator& operator -- (int){

                                    // backward the iterator by one position to the left

                        }

                        Iterator operator -- (){

                                    // postfix  version

                        };

            private:

                        List* list;                  // pointer to current doubly linked list object

                        Node* cNode;         // pointer to the node in the doubly linked list

};

// Main driver program

#include "List.h"

#include

#include

using namespace std;

 

typedef List ListD;

typedef List ListI;

typedef List ListS;

int main(){

            ListD    x;

            x.push_front(4.4); x.push_front(3.3); x.push_front(2.2); x.push_front(1.1);

 

            ListD y(x);

            ListD z = x;

            // output is shown in the text box 1

            cout<< "x.front = "<< x.front()<< endl;   

            cout<< "List x ="<

            cout<< "x.size() ="<< x.size()<< endl;

            while(!x.empty()){

                        cout<< x.front()<< endl;

                        x.pop_front();

            }

           cout<< "x.size() now = "<< x.size()<< endl;

            cout<< "List y ="<

            cout<< y<< endl;

            cout<< "List z ="<

            cout<< z<< endl;

            ListD v;

            v = y;

            v.pop_front();

                        // output is show in the text box  2

             cout<< "List v (v = y; v.pop_front();) ="<

            cout<< v<< endl;

            ListI li;

            li.push_front(3); li.push_front(2); li.push_front(1);

                        // output is show in the text box 3

            cout<< "List li via operator <<"<

            cout<< li<< endl;

            li.push_back(22);

            li.push_back(33);

                        // output is show in the text box 4

            cout<< "li.push_back(22), li.push_back(33)"<< endl;

            cout<< li<< endl;

            cout<< "back(), pop.back()"<< endl;

            while(!li.empty()){

                        cout<< li.back()<< endl;

                        li.pop_back();

            }

           ListS ls;

            ls.push_front("abcd");

            ls.push_front("cdefgh");

            ls.push_back("back");

            cout<< ls<< endl;          // output is show in the text box 5

            ListI c5;

            for(uint i = 0; i< 5; ++i){

                        c5.push_back(i);

                        cout<< "c5.push_back(i = "<< i<< "): "<< c5;  // output is show in the text box6

            }

           cout<< "using Iterator"<< endl;   // output is show in the text box 7                   

            ListI::Iterator itr = c5.begin();

            ListI::Iterator itrb = c5.begin();

            ListI::Iterator itre = c5.end();

            if(itr == itrb)       cout<< "itr == itrb"<< endl;

            else cout<< "itr != itrb"<< endl;

            if(itr != itrb)        cout<< "itr != itrb"<< endl;

            else cout<< "itr == itrb"<< endl;

            ListI::Iterator it;

            for(it = c5.begin(); it != c5.end(); ++it){

                        cout<< *it<< ' ';             // output is show in the text box 7

            }

            // output is show in the text box 8

            cout<< "ListI::Iterator itr2 = c5.begin(), ++, ++ "<< endl;

            cout<< "c5.insert(itr2, 5, 33) "<< endl;

            ListI::Iterator itr2 = c5.begin();

            itr2++; itr2++;

            c5.insert(itr2, 5, 33);

            cout<< c5;

            return 0;

}


Related Discussions:- Design a doubly linked list

Travelling salesman problem, Example 3: Travelling Salesman problem G...

Example 3: Travelling Salesman problem Given: n associated cities and distances among them Find: tour of minimum length that visits all of city. Solutions: How several

First class Abstract data type , 3. A function to convert a complex number ...

3. A function to convert a complex number in algebraic form to a complex number in phasor form

Design a framework of a genetic algorithm, You have to design a framework o...

You have to design a framework of a Genetic Algorithm (GA) with basic functionality. The basic functionality includes representation, recombination operators, tness function and se

Determine yiq colour model, Determine YIQ Colour Model Whereas an RGB m...

Determine YIQ Colour Model Whereas an RGB monitor requires separate signals for the red, green, and blue components of an image, a television monitor uses a single composite si

Binary search tree, write an algorithm to delete an element x from binary...

write an algorithm to delete an element x from binary search with time complex

Explain threaded binary tree, Threaded Binary Tree : If a node in a bin...

Threaded Binary Tree : If a node in a binary tree is not having left or right child or it is a leaf node then that absence of child node is shown by the null pointers. The spac

Flowchart, create a flowchart that displays the students average score for ...

create a flowchart that displays the students average score for these quizzes

What are the languages which support assertions, What are the languages whi...

What are the languages which support assertions Languages which support assertions often provide different levels of support. For instance, Java has an assert statement which t

Two - way merge sort, Merge sort is also one of the 'divide & conquer' clas...

Merge sort is also one of the 'divide & conquer' classes of algorithms. The fundamental idea in it is to split the list in a number of sublists, sort each of these sublists & merge

Arrays, Data array A has data series from 1,000,000 to 1 with step size 1, ...

Data array A has data series from 1,000,000 to 1 with step size 1, which is in perfect decreasing order. Data array B has data series from 1 to 1,000,000, which is in random order.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd