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Q. Counter-controlled analog to digital converter?
Figure shows the block diagram of a counter-controlledA/Dconverter. Resetting the binary counter to zero produces D/A output voltage V2 = 0 and initiates the analog-to-digital conversion. When the analog input V1 is larger than the DAC (D/A converter) output voltage, the comparator output will be high, thereby enabling the AND gate and incrementing the counter. V2 is increased
as the counter gets incremented; when V2 is slightly greater than the analog input signal, the comparator signal becomes low, thereby causing the AND gate to stop the counter. The counter output at this point becomes the digital representation of the analog input signal. The relatively long conversion time needed to encode the analog input signal is the major disadvantage of this method.
Q. Use (a) mesh analysis and (b) nodal analysis to determine the current through the 4-resistor of the circuit of Figure.
Explain Einstein relation. Einstein relation: There exists a significant relation between the diffusion constant and the mobility. It is termed as the Einstein relation and
Q. Smallest unit of information on a machine? Short for the binary digit the smallest unit of information on a machine. This term was first used in 1946 by the John Tukey, a le
Q. Can you explain twos Complement Division? 2's complement division is repeated 2's complement subtraction. The 2's complement of the divisor is calculated, and then added to
.coments on the limitation of the superposition theorem
Common-emitter configuration: The common-emitter that is abbreviated as CE transistor configuration is displayed in figure. The transistor terminal common to both the input
Buck Boost Converter The output of buck boost regulator may be less than or greater than the input voltage. Since the polarity of output voltage is opposite to that
Case 2 ( A>B) Suppose XX = 05H ( stored in A ) And YY = 02H ( stored in B). Then carry flag will reset by CMP instruction, since A> B in this case JNC will transfer the
explain the alphanumeric codes
the p.u. reactance of a 25 MVA, 13.2 kV alternator 0.5 p.u. On a base of 50 MVA and 13.8 KV the p.u. value shall be
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