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Define Constant argument:
The argument can be a constant argument. The constant variable cannot be changed inside the function definition when the argument is declared as constant.
void f_const(int x, const int y);
void main( )
{int a10, b=20,c;
c =f_const(a, b); //The value of c is 30
}
int f_ref(int x, const int y)
{ //y=20; // Is invalid because y is declared as constant variable. return (x+y);
void f_const(int x, const int y=100);
{int a=200, b,c;
c =f_const(a); //The value of c is 300
int f_const(int x, const int y)
Can you overload a function depend only on whether a parameter is a value or a reference? A: No. Passing by value and reference looks identical to the caller.
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What if one can''t wrap the local in an artificial block?
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