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Insertion sort - C program:
Write a program in c to define a insertion sort.
void main()
{
clrscr();
int a[100],ch,n;
cout<<"enter the limit for the array : ";
cin>>n;
for (int i=0;i { cout<<"enter element "< cin>>a[i]; } clrscr(); cout<<"1. insertion sorting "< isort(a,n); } } void isort(int a[100],int n) { clrscr(); int te,i,j; for(i=1; i { te=a[i]; j=i-1; while (te=0) { a[j+1]=a[j]; j=j-1; } a[j+1]=te; } cout<<" sorted arrays by insertion "<<"\n\n"; for(i=0; i cout< getch(); }
cout<<"enter element "<
cin>>a[i];
}
cout<<"1. insertion sorting "< isort(a,n); } } void isort(int a[100],int n) { clrscr(); int te,i,j; for(i=1; i { te=a[i]; j=i-1; while (te=0) { a[j+1]=a[j]; j=j-1; } a[j+1]=te; } cout<<" sorted arrays by insertion "<<"\n\n"; for(i=0; i cout< getch(); }
isort(a,n);
void isort(int a[100],int n)
int te,i,j;
for(i=1; i { te=a[i]; j=i-1; while (te=0) { a[j+1]=a[j]; j=j-1; } a[j+1]=te; } cout<<" sorted arrays by insertion "<<"\n\n"; for(i=0; i cout< getch(); }
te=a[i];
j=i-1;
while (te=0)
a[j+1]=a[j];
j=j-1;
a[j+1]=te;
cout<<" sorted arrays by insertion "<<"\n\n";
for(i=0; i cout< getch(); }
cout< getch(); }
getch();
There are 3 acceptable answers: "Never," "Rarely "and" When the problem domain cannot be accurately modelled any other way."
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