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Consider the following relational schema: PERSON (SS#, NAME, ADDRESS) CAR (REGISTRATION_NUMBER, YEAR, MODEL) ACCIDENT (DATE, DRIVER, CAR_REG_NO) OWNS (SS#, LICENSE)
Construct the subsequent relational algebra queries: (i) Find out the names of persons who are included in an accident. (ii) Find out the registration number of cars that were not involved in any accident. Ans: (i) πNAME(PERSON) ∩ πDRIVER(ACCIDENT) (ii) πREGISTRATION_NUMBER(CAR) - πCAR_REG_NO(ACCIDENT)
explain normalisation
Compare wait-die deadlock prevention scheme with wait-wound scheme Ans: Wait-Die Scheme a) Based upon a nonpreemptive technique. b) If Pi requests a resource present
what do you mean by consistency in rdbms?
What is horizontal fragmentation? Horizontal fragmentation divides the relation by assuming every tuple of r to one or more fragments
One-way Associations When an association is traversed only in the one direction, then it is implemented as a pointer i.e.an attribute which contains an object reference. If mu
What are the three classes of SQL expression? SQL expression consists of three clauses: Select From Where
A domain is a set of permissible values that can be given to an attribute. So each attribute in a table has a definite domain. Values to these attributes cannot be assigned outside
Question 1 Discuss on transmission impairments Question 2 What is framing? Question 3 Write a note on 10Base2 10Base- T Question 4 Explain the rev
Compare three clustering algorithms in Weka. For this comparison, you will need to use at least two different datasets. Run the algorithms on the datasets, and use the visual
Chapter 1 - Profile for the Organization You have to select an organization of your choice and assume that you work for that organization. Now you must prepare a brief profile of t
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