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Now we start solving constant linear, coefficient and second order differential and homogeneous equations. Thus, let's recap how we do this from the previous section. We start alon
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Using the expample provided below, if m∠ABE = 4x + 5 and m∠CBD = 7x - 10, Determine the measure of ∠ABE. a. 155° b. 73° c. 107° d. 25° d. ∠CBD and ∠ABE are vert
Write the next two terms √12, √27, √48, √75................... Ans: next two terms √108 , √147 AP is 2 √3 , 3 √3 , 4 √3 , 5 √3 , 6 √3 , 7 √3 ......
Finds out the center & radius of each of the following circles & sketch the graph of the circle. a) x 2 + y 2 = 1 b) x 2 + ( y - 3) 2 = 4 Solution In all of these
Here we will use the expansion method Firstly lim x-0 log a (1+x)/x firstly using log property we get: lim x-0 log a (1+x)-logx then we change the base of log i.e lim x-0 {l
Multiply following. Assume that x is positive. (3√x-√y)(2√x-5√y) Solution (3√x-√y)(2√x-5√y) =6√x 2 -15√x√y-2√x√y+5√y
1-tan^2 A/1+tan^2 = cos A - sinA/cos A
algorithm of cosx
Initial Conditions and Boundary Conditions In many problems on integration, an initial condition (y = y 0 when x = 0) or a boundary condition (y = y
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