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Question:
Q1) Write a code that asks the user for a positive integer, computes the square root of that integer, and return the result to the user. The computational error needs to be smaller than 0.01.
1. Get a positive integer 'X' as the input.
2. Start from an initial guess, G.
3. Compute the error = (G^2 - X).
4. If error < 0.01, report the G as the result and stop. If not, go to 5.
5. Update G, G = (G + X/G)/2. Go to 3.
Code Block
//This program computes the square root of a given positive integer and is written by Vahid D on 13/1/13
#include using namespace std; int main() { double G = 10, err; // G is an initial guess and err is the error int X; // input, positive integer cout << "Enter a positive integer: \n"; //ask user to enter a number cin >> X; // get the input err = (G*G - X); // compute the error while ( err > 0.01) // continue updating G till the error is smaller than 0.01 { G = (G + X/G)/2; err = (G*G - X); } cout << "Square root of " << X << " is: " << G << endl; // report the result return 0; }
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f(x)^2=f(x) - x
is this free
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