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CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a memory location. For the purpose of comparison, it subtracts the source operand from the destination operand but does not stock up the result anywhere. The flags are affected and depending on the result of the subtraction. If both of the operands are equal to zero flag is set. If the source operand is higher than the destination operand, carry flag is set or else is reset. The instance of this instruction are following:
Example :
1. CMP BX, 0100H Immediate
2. CMP 0100 Immediate [AX implicit]
3. CMP [5000H],OIOOH Direct
4. CMP BX, [SI] Register indirect
5. CMP BX, CX Register
Memory Address Decoding Binary Decoders - Decoders have 2n-inputs and n outputs, each input combination results in a single output line contain a 1, and all other lines contain
Task One Produce a menu such as the one below (remember to keep to this specification). M E N U 1, Enter Number 1 2, Enter Number 2 3, Display num1 and num2 4, D
IMUL: Signed Multiplication: This instruction multiplies a signed byte by a signed bit in source operand e in the register AL or signed word in source operand by signed word in th
what is implied addressing
HELLO I AM TRYING TO ADD AND SUBTRACT BUT I SEEM CAN''T FIND THE CORRECT REGISTER TO PUT IN
NEG: Negate:- The negate instruction forms the 2's complement of the particular destination in the instruction. For obtaining 2's complement, it subtracts the contents of destinat
DW : Define Word:- The DW directive serves the same purposes as the DB directive, but now it makes the assembler which reserves thenumber ofmemory words (16-bit) instead of by
DQ: Define Quad word:- This directive is taken in use to direct the assembler to reserve 4 words (8 bytes) of memory for the specified variable and can initialise it having
8088 Timing System Diagram The 8088 address/data bus is divided in 3 parts (a) the lower 8 address/data bits, (b) the middle 8 address bits, and (c) the upper 4 status/
Write a program to mask bits D3D2D1D0 and to set bits D5D4 and to invert bits D7D6 of ax register
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