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CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a memory location. For the purpose of comparison, it subtracts the source operand from the destination operand but does not stock up the result anywhere. The flags are affected and depending on the result of the subtraction. If both of the operands are equal to zero flag is set. If the source operand is higher than the destination operand, carry flag is set or else is reset. The instance of this instruction are following:
Example :
1. CMP BX, 0100H Immediate
2. CMP 0100 Immediate [AX implicit]
3. CMP [5000H],OIOOH Direct
4. CMP BX, [SI] Register indirect
5. CMP BX, CX Register
DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in t
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Tabular comparison for µ PS' Parameters Tables (a) and (b) list the characteristic of Intel microprocessor. Table(a): Table(b): It has a 64 bit da
Control Transfer or Branching Instruction Control transfer instructions transfer the flow of execution of the program to a new address specified in the instruction indirectly o
Interrupt When the CPU detects an interrupt signal, it stops activity of current and jumps to a special routine, known an interrupt handler. This handler then detects why the i
.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX
Typical link to modems for synchronous and asynchronous transmissions are shown in Figure. With regard to the synchronous connections it is consider that the timing is controlled
This unit introduces the topic of evaluating interactive products. It is a short unit as evaluation is discussed in more detail in Block 4. Its brevity should give you additional t
8279 Keyword /Display Controller : Figure shows the structure of 8279 and its interface to the bus. Addressing is according to the table given below. CS RD
Problem (a) Prepare the assembly code sequence for each of the four styles (accumulator, memory-memory, stack, load/store) of machine for the code fragment: A = B + C;
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