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In a circular linked list
There is no beginning and no end.
Algorithm for determining strongly connected components of a Graph: Strongly Connected Components (G) where d[u] = discovery time of the vertex u throughout DFS , f[u] = f
File organisation might be described as a method of storing records in file. Also, the subsequent implications approaching these records can be accessed. Given are the factors invo
(1) (i) Add the special form let to the metacircular interpreter Hint: remember let is just syntactic sugar for a lambda expression and so a rewrite to the lambda form is all t
The advantage of list over Arrays is flexibility. Over flood is not a problem until the computer memory is bushed. When the individual record are quite large, it may be difficult t
Suppose there are exactly five packet switches (Figure 4) between a sending host and a receiving host connected by a virtual circuit line (shown as dotted line in figure 4). The tr
I =PR/12 Numbers of years .Interest rate up to 1yrs . 5.50 up to 5yrs . 6.50 More than 5 yrs . 6.75 design an algorithm based on the above information
Comp are two functions n 2 and 2 n / 4 for distinct values of n. Determine When s ec on d function b ec om es l a r g er th an f i r st functi
Q. Devise a representation for a given list where insertions and deletions can be made at both the ends. Such a structure is called Deque (which means Double ended queue). Write fu
Q. Consider the specification written below of a graph G V(G ) = {1,2,3,4} E(G ) = {(1,2), (1,3), (3,3), (3,4), (4,1)} (i) Draw the undirected graph. (
a. Determine the result of inserting the keys 4,19, 17, 11, 3, 12, 8, 20, 22, 23, 13, 18, 14, 16, 1, 2, 24, 25, 26, 5 in order to an empty B-Tree of degree 3. Only draw the configu
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