Centre of gravity, Physics

Assignment Help:

CENTRE OF GRAVITY:

2298_center of gravity.png

Consider a body as an accumulation of many small masses (molecules), all subject to gravitational attraction.  The total weight, which is a force, is equal to the sum of the individual masses, multiplied by the gravitational acceleration(g =9.81 m/s2).

          W  =  mg
The diagram shows that the individual forces all act in the same direction, but have different lines of action.

412_center of gravity1.png
There must be datum position, such that the total moment to one side, causing a clockwise rotation, is balanced by a total moment, on the other side, which causes an anticlockwise rotation.  In other words, the total weight can be considered to act through that datum position (=  line of action).

1989_center of gravity2.png

If the body is considered in two different position, the weight acts through two lines of action, W1 and W2 and these interact at point G, which is termed the Centre of Gravity.

Hence, the Centre of Gravity is the point through which the Total Mass of the body may be considered to act.

For a 3-dimensional body, the centre of gravity can be determined practically by several methods, such as by measuring and equating moments, and thus is done when calculating Weight and Balance of aircraft.

A 2-dimensional body (one of negligible thickness) is termed a lamina, which only has area (not volume).  The point G is then termed a Centroid.  If a lamina is suspended from point P, the centroid G will hang vertically below 'P1'.  If suspended from P2  G will hang below P2.  Position G is at the intersection as shown.

A regular lamina, such as a rectangle, has its centre of gravity at the intersection of the diagonals.

1943_center of gravity3.png

Other regular shapes have their centre of gravity at known positions, see the table below.

1113_center of gravity4.png

778_center of gravity4.png

A triangle has its centre of gravity at the intersection of the medians.

1330_center of gravity5.png

318_center of gravity6.png

The centre of gravity can also be deduced as shown.

If the lamina is composed of a several regular shapes, the centre of gravity of that lamina can be deduced by splitting it into its regular sections, calculating the moments of these areas about a given datum, and then equating the sum of these moments to the moment of the composite lamina.

2129_center of gravity7.png


Expressed as an algebraic formula,

          A, X,  +  A2 X2  +  A3 X3  =  (A1 + A2 + A3) 1488_center of gravity8.png

 

Where  1488_center of gravity8.pngis the position of the centroid, with respect to the datum. This is the principle behind Weight and Balance.


Related Discussions:- Centre of gravity

Construction and working of michelson interferometer, Q.   Describe the con...

Q.   Describe the construction and working of Michelson Interferometer. Explain how you will determine the wavelength difference of two components of a line by Michelson Interferom

Refractive astronomical telescope, Refractive Astronomical Telescope: I...

Refractive Astronomical Telescope: It is an optical instrument which is used to see heavenly bodies such as stars, moon and planets is known as telescope. Astronomical teles

What is incorrect with the way, A person is determining the description of ...

A person is determining the description of the image formed by a converging lens by implies of a ray tracing diagram. The person has gotten so far as drawing one principal ray. Wha

What is band emission spectrum, Q. What is band emission spectrum? Give an ...

Q. What is band emission spectrum? Give an example. It consists of a numerous bright bands with a sharp edge at one end but fading out at the other end. Band spectra are acquir

Give a mathematical expression for linear width, Give a mathematical expres...

Give a mathematical expression for linear width of principal maxima in case of single slit Fraunhofer diffraction.

Nuclear, how proton electron hypothesis is rejectrd on the basis of nuclear...

how proton electron hypothesis is rejectrd on the basis of nuclear magnetic dipole moment?

Rutherford’s gold - foil experiment , An α particle is a positively charged...

An α particle is a positively charged particle. Rutherford observed the behaviour of these particles when they approach the interior of the atoms as shown in fig.  Rutherford ob

Evaluate voltage across the capacitor, Ques: For the case of a capacito...

Ques: For the case of a capacitor which is originally charged and then connected across a resistor the charge on the capacitor the voltage across the capacitor and the current

Vector, Find the resultant of two vectors defined as A=6km east B=8km nort...

Find the resultant of two vectors defined as A=6km east B=8km north

Planck equation, Planck equation The quantum mechanical equation relati...

Planck equation The quantum mechanical equation relating to the energy of a particular photon E to its frequency nu: E = h nu.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd