Centre of gravity, Physics

Assignment Help:

CENTRE OF GRAVITY:

2298_center of gravity.png

Consider a body as an accumulation of many small masses (molecules), all subject to gravitational attraction.  The total weight, which is a force, is equal to the sum of the individual masses, multiplied by the gravitational acceleration(g =9.81 m/s2).

          W  =  mg
The diagram shows that the individual forces all act in the same direction, but have different lines of action.

412_center of gravity1.png
There must be datum position, such that the total moment to one side, causing a clockwise rotation, is balanced by a total moment, on the other side, which causes an anticlockwise rotation.  In other words, the total weight can be considered to act through that datum position (=  line of action).

1989_center of gravity2.png

If the body is considered in two different position, the weight acts through two lines of action, W1 and W2 and these interact at point G, which is termed the Centre of Gravity.

Hence, the Centre of Gravity is the point through which the Total Mass of the body may be considered to act.

For a 3-dimensional body, the centre of gravity can be determined practically by several methods, such as by measuring and equating moments, and thus is done when calculating Weight and Balance of aircraft.

A 2-dimensional body (one of negligible thickness) is termed a lamina, which only has area (not volume).  The point G is then termed a Centroid.  If a lamina is suspended from point P, the centroid G will hang vertically below 'P1'.  If suspended from P2  G will hang below P2.  Position G is at the intersection as shown.

A regular lamina, such as a rectangle, has its centre of gravity at the intersection of the diagonals.

1943_center of gravity3.png

Other regular shapes have their centre of gravity at known positions, see the table below.

1113_center of gravity4.png

778_center of gravity4.png

A triangle has its centre of gravity at the intersection of the medians.

1330_center of gravity5.png

318_center of gravity6.png

The centre of gravity can also be deduced as shown.

If the lamina is composed of a several regular shapes, the centre of gravity of that lamina can be deduced by splitting it into its regular sections, calculating the moments of these areas about a given datum, and then equating the sum of these moments to the moment of the composite lamina.

2129_center of gravity7.png


Expressed as an algebraic formula,

          A, X,  +  A2 X2  +  A3 X3  =  (A1 + A2 + A3) 1488_center of gravity8.png

 

Where  1488_center of gravity8.pngis the position of the centroid, with respect to the datum. This is the principle behind Weight and Balance.


Related Discussions:- Centre of gravity

Instantaneous velocity and instantaneous speed, Can instantaneous velocity ...

Can instantaneous velocity answer instantaneous speed be equal in uniform motion

why the vectors do not divide?, Actually vectors are divisible but not dir...

Actually vectors are divisible but not directly. A vector is multiplied by the inverse of the vector to be divided.In other way, its magnitude an be divided and multiplied by a uni

Moment of inertia, A non-uniform rod AB has a mass M and length 2l.The mass...

A non-uniform rod AB has a mass M and length 2l.The mass per unit lengthof the rod is mx at a point of the rod distant x from A. find the moment of inertia of this rod about an axi

Modern physics: Relativity, A student finds that a particle whose life is m...

A student finds that a particle whose life is micro-sec (µ- sec) moves with a velocity of 2.7 x 108 m/sec. i) What will be its lifetime as measured by another observer in the labor

Low resistivity materials, Low resistivity materials: The conducting mater...

Low resistivity materials: The conducting materials having resistivity between 10 -8 to 10 -6 ohm-m come under this category and are used in house wiring, as conductors for powe

At what upward acceleration will the string break, A 10.0-kg object is held...

A 10.0-kg object is held up by a string that will break when the tension exceeds 1.00 x 10 2 N. At what upward acceleration will the string break?

Combined field due to the earth and a bar magnet, Where do you find the nul...

Where do you find the null points in the combined field due to the earth and a bar magnet, when i) the N-pole of the magnet is taken towards the north of the earth, ii) the

What are the applications of nmr spectroscopy, What are the applications of...

What are the applications of nmr spectroscopy? The major applications of NMR stereoscopy are the elucidation of the carbon-hydrogen backbone of organic compounds and the determ

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd