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Capacitor Filter:
A capacitor filter is connected directly across the load is displayed in figure. The property of a capacitor is that it permits ac component and blocks dc (direct current) component. The operation of the capacitor filter is for short the ripple to ground but leave dc (direct current) to emerge at output when it is connected across the pulsating dc voltage.
Throughout the positive half cycle, the capacitor charges equal to the peak vale of the transformer secondary voltage, Vm and will try to keep this value since the full wave input drops to zero. Capacitor will discharge via RL slowly till the transformer secondary voltage again gets increases to a value greater as compared to the capacitor voltage. The diode conducts for a period that depends upon the capacitor voltage. The diode will conduct while the transformer secondary voltage becomes much more than the diode voltage. This is termed as cut in voltage. The diode stops conducting while the transformer voltage becomes less as compared to the diode voltage. This is known as cut out voltage.
Q. What do you mean by Output Voltage Swing? Ideally this is equal to the difference between the two supply rail voltages, although in practice it is a few volts less.
Draw the state diagram for the state machine described by Table 7.5 in the text. Note, the table shows the transition to the next state S* from the current state S for the next set
Q. Explain about Capital stock? Capital stock illustrates the amount of the owners' investment in the corporation.
Collection and Payment Systems Payments are currently made in person in most of the places. Only some places payments could be made on line or by the ATM (Automated Teller Mac
a) A 230 V/25V, 50 HZ transformer with a rated primary current of 1,2 Amps is used to supply a number of 25 V, 30 Watt halogen light bulbs. Assuming an ideal transformer and that
A 100kw,230v,dc shunt generator,with Ra=0.05,and Rf=57.5 has no load rotational loss(friction,wandage,core loss)of 1.8kw.compute a) The generator efficiency at full load.
A DC shunt motor rotating at 1560 RPM is supplied from a 240-V source. The line current supplied to the motor is equal to 27 A. The shunt field resistance of the motor is equal to
POP PSW Instruction It is similar to above pop instruction but instead of normal register pairs it uses PSW as its operand. Program status word comprises of the content
Microprocessor and its Applications
Common-emitter configuration: The common-emitter that is abbreviated as CE transistor configuration is displayed in figure. The transistor terminal common to both the input
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