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The vertices of a ? ABC are A(4, 6), B(1. 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that AD/AB = AE/AC = 1/4 .Calculate the area of the Δ ADE and compare it with the area of Δ ABC.(Ans: 15/32 sq units; 1:16)
Ans : Hint :
AD/AB = AE /AC= 1/4
∴ AD : DB = 1 : 3 & AE : EC = 1 : 3
Find D & E and find area of triangle ADE and triangle ABC and compare.
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