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A piece of cardboard in the shape of a trapezium ABCD & AB || DE, ∠BCD = 900, quarter circle BFEC is removed. Given AB = BC = 3.5 cm, DE = 2 cm. Calculate the area of remaining piece of cardboard. (Ans:6.125 cm2)
Ans: Area of remaining portion = Area of trap - Area of quadrant
= 1/2 x 3.5 (5.5 + 3.5) - 1/4 x 22/7 x3.5x3.5
= 15.75 - 19.25/2 = 15.75 - 9.625
= 6.125 cm2
el extremo de un poste que partió 8.45 metros de la base del poste y forma con el suelo un angulo de 40 grados 28 minutos.hallar la altura original del poste
solve the differential equation 8yk+2-6yk+1+yk=9 ,k=0 given that Y0=1 and y1=3/2
use venn diagram to present
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Find the amount of sheet metal need to form a conical funnel of base radius 30cm with a vertical height of 50cm, allowing for 0.5cm overlap. Find the total surface area?
suppose you a business owner and selling cloth. the following represents the number of items sold and the cost for each item. use matrix operation to determine the total revenue ov
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Solve the subsequent differential equation. 2xy - 9 x 2 + (2y + x 2 + 1) dy/dt = 0 Solution Let's start off via supposing that wherever out there in the world is a fun
Tetracycline 500 mg capsules Sig: 1 cap po bid for 14 days. Refills: 2 What is the dose of this medication:____________________ (0.5 point) How many doses are given per day:______
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