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A piece of cardboard in the shape of a trapezium ABCD & AB || DE, ∠BCD = 900, quarter circle BFEC is removed. Given AB = BC = 3.5 cm, DE = 2 cm. Calculate the area of remaining piece of cardboard. (Ans:6.125 cm2)
Ans: Area of remaining portion = Area of trap - Area of quadrant
= 1/2 x 3.5 (5.5 + 3.5) - 1/4 x 22/7 x3.5x3.5
= 15.75 - 19.25/2 = 15.75 - 9.625
= 6.125 cm2
The vertices of a ? ABC are A(4, 6), B(1. 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that AD/AB = AE/AC = 1/4 .Calculate the ar
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