Calculate heat energy required, Chemistry

Assignment Help:

Calculate how much heat energy is required to raise the temperature of a cube of copper of side 2cm. from 300 to 320k. given: density=8933kg/m cube , atomic weight=63.55, cp=24j/k/mole

Related Discussions:- Calculate heat energy required

organic chemistry, Synthesis of di and tri substituted benzene

Synthesis of di and tri substituted benzenes

What is chemistry, what is chemistry

what is chemistry

Chemical kinetics, Distinguish between van''t Hoff Method and Oswald Isolat...

Distinguish between van''t Hoff Method and Oswald Isolation Method. In each case give an expression for the rate of reaction.

Periodic table, how periodic table is helpful in chemistry give two example...

how periodic table is helpful in chemistry give two example

Expalin le chteliers principle, Q. Explain Le Chtelier's Principle Ans...

Q. Explain Le Chtelier's Principle Ans. Consider the equilibrium reaction of: A + B -> C + D The forward reaction occurs when A and B combine to form C and D: A +

Full Balanced Equations, #question.What is the balanced equation for the re...

#question.What is the balanced equation for the reaction of aluminium nitrate solution and sodium carbonate solution; where aluminium hydroxide is formed.

Molecular obital theory, videos

videos

The formation of energy bonds in solids are in accordance, The formation of...

The formation of energy bonds in solids are in accordance with: (1) Heisenberg's uncertainty principle (2)Bohr's theory (3 )Ohm's law (4) Rutherford's atomic model

Hardness of water explain various units and their relationsh, maxmium 500 w...

maxmium 500 words

Sericulture, Is sericulture possible at 35 dgree centigrade?

Is sericulture possible at 35 dgree centigrade?

Anna 3/29/2013 3:56:15 AM Heat energy required = mcT mass=d.v=8933 . (.02)^3 = .0712 kg = 71.2 gm mo of moles = 71.2 / 63.55 = 1.12 moles c=24 j/k-mole. T=20 H= (1.12) . 24 . 20 =537.6 Joules (ANS)

Anna

3/29/2013 3:56:15 AM

Heat energy required = mcT
mass=d.v=8933 . (.02)^3 = .0712 kg = 71.2 gm
mo of moles = 71.2 / 63.55 = 1.12 moles
c=24 j/k-mole.
T=20
H= (1.12) . 24 . 20
=537.6 Joules (ANS)

Write Your Message!

Name

Email id

Message

Verfication Code

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

Submit Assignment

User Account

All Pages