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Memory-to-Memory Architecture
The pipelines can access vector operands intermediate and final results straight in main memory. This necessitates the higher memory bandwidth. Furthermore the information of the offset, base address, vector length must be specified for transferring the data streams between the pipelines and main memory. TI-ASC and STAR-100 computers have accepted this architecture for vector instructions.
Assignment 2: K-nearest neighbor for text classification. The goal of text classification is to identify the topic for a piece of text (news article, web-blog, etc.). Text clas
State the drawbacks of laptop compared to PC The main disadvantages of laptops compared to desk top PCs are: - They tend to be more expensive to purchase - It's easie
What are advantages and drawbacks of flip-flop? Usually area of a Flip-flop for features in more than a latch. Power consumption is normally higher, because of the area and
Q. How to load DOS from Floppy Disk? If DOS is not setup on the Hard Disk of your PC, or you want to load DOS from the Floppy disk drive due to any reason, follow these steps:
Hyper cube or multidimensional cube forms the core of OLAP system. This having of measures which are arranged according to dimensions. Hyper cube Meta data is formed by star or sno
Q. Illustrate what is a ion pair energy? Answer:- Ion energy contains electric charges called protons (+) and neutrons (0) and electrons (-) charges. It's present in an at
Subtraction of 01100-00011 using 2's complement method Ans. Firstly 1's complement of 00011 is 11100 and 2's complement is 11100 + 1 = 11101. Thus If a last carry is
Define Encapsulation- object-oriented technology Encapsulation also called as information hiding, is the characteristic of separating the external aspects of an object, from t
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b
Write down the basic performance equation? T=N*S/R T=processor time N=no.of instructions S=no of steps R=clock rate
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