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if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?
Let's go through first form of the parabola. f ( x ) = a ( x - h ) 2 + k There are two pieces of information regarding the parabola which we can instant
330 radians
what is the answer to y is greater than 3x-l and y is less than x+2
Solve following equations. (a) x 2 -100 = 0 (b) 25 y 2 - 3 = 0 Solution There actually isn't all that much to these problems. To use the square root property a
We've dealt along with this function many times already. Now it's time to graph it. First, let's remember ourselves of the definition of the absolute value function. It is a pie
(2x^2+16x+24)/(3x^2) /(x+6)
In this last section we have to discuss graphing rational functions. It's is possibly best to begin along a rather simple one that we can do with no all that much knowledge on how
Write the equation of the circle in standard form. Find the center, radius, intercepts, and graph the circle. x2+y2+16x-18y+145=25
Example: Solve following equations. 2 log 9 (√x) - log 9 (6x -1) = 0 Solution Along with this equation there are two logarithms only in the equation thus it's easy t
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