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Assume a complete binary tree T with n nodes where each node has an item (value). Label the nodes of the complete binary tree T from top to bottom & from left to right 0, 1, ..., n-1. Relate with T the array A where the ith entry of A is the item in the node labeled i of T, i = 0, 1, ..., n-1. Table illustrates the array representation of a Binary tree of Figure
Given the index i of a node, we can efficiently & easily compute the index of its parent and left & right children:
Index of Parent: (i - 1)/2, Index of Left Child: 2i + 1, Index of Right Child: 2i + 2.
Node #
Item
Left child
Right child
0
A
1
2
B
3
4
C
-1
D
5
6
E
7
8
G
H
I
J
9
?
Table: Array Representation of a Binary Tree
First column illustrates index of node, second column contain the item stored into the node & third & fourth columns mention the positions of left & right children
(-1 shows that there is no child to that specific node.)
Draw trace table and determine output from the subsequent flowchart using below data: X = 5, -3, 0, -3, 7, 0, 6, -11, -7, 12
Program segment for deletion of any element from the queue delete() { int delvalue = 0; if (front == NULL) printf("Queue Empty"); { delvalue = front->value;
While BFS is applied, the vertices of the graph are divided into two categories. The vertices, that are visited as part of the search & those vertices that are not visited as part
Q. Define a method for keeping two stacks within a single linear array S in such a way that neither stack overflows until entire array is used and a whole stack is never shifted to
explanation with algorithm
What are expression trees? The leaves of an expression tree are operands, like as constants or variable names, and the other nodes have operators. This certain tree happens to
The complexity Ladder: T(n) = O(1). It is called constant growth. T(n) does not raise at all as a function of n, it is a constant. For illustration, array access has this c
Like general tree, binary trees are implemented through linked lists. A typical node in a Binary tree has a structure as follows struct NODE { struct NODE *leftchild; i
Example of worse case of time
1. Write a pseudocode algorithm to print the numbers from 1 to 10, and then from 10 to 1, using exactly one loop. 2. The function contains() takes a food as an argument and tell
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