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Suppose a regular polygon, which is an N-sided with equal side lengths S and similar angles at each corner. There is an inscribed circle to the polygon that has center C and barely touches the midpoint of every part. A line from C to the midpoint of a side is known as the apothem, and consider this apothem has length R.
If you cut the polygon along staright lines from each corner of the polygon to the center C, you can get a bunch of triangles, each with area (1/2)*(base)*(height). Note that every (base) has length S and the (height) is the length R of the apothem, and there are N such triangles. Therefore the total area of the polygon is N*(1/2)*S*R, which to say it another way is:
(1/2) (Circumference of the Polygon) * R
Simpson's Rule - Approximating Definite Integrals This is the last method we're going to take a look at and in this case we will once again divide up the interval [a, b] int
Ask questioOn average, Josh makes three word-processing errors per page on the first draft of his reports for work. What is the probability that on the next page he will make a) 5
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Without solving, find out the interval of validity for the subsequent initial value problem. (t 2 - 9) y' + 2y = In |20 - 4t|, y(4) = -3 Solution First, in order to u
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the sides of a right angle triangle are a,a+d,a+2d with a and d both positive.the ratio of a to d a)1:2 b)1:3 c)3:1 d)5:2 answer is (c) i.e. 3:1 Solution: Applying
Here is not too much to this section. We're here going to work an illustration to exemplify how Laplace transforms can be used to solve systems of differential equations. Illus
Determine the solution to the subsequent differential equation. dv/dt = 9.8 - 0.196v Solution Initially we require finding out the differential equation in the accurate
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lbl 2 lcl 2 sin 2 θ
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